A balanced lever has two weights on it, the first with mass $12 k g$ $12 kg$ and the second with mass $36 k g$ $36 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-04-16T12:37:47

The distance is $= 1.33 m$ $=1.33m$

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Mass, $M_{2} = 12 k g$ $M_2=12kg$

Mass, $M_{1} = 36 k g$ $M_1=36kg$

Distance, $b = 4 m$ $b=4m$

Taking moments about the fulcrum

$M_{1} \cdot a = M_{2} \cdot b$ $M_1*a=M_2*b$

$a = \frac{M_{2}}{M_{1}} \cdot b$ $a=M_2/M_1*b$

$= \frac{12 g}{36 g} \cdot 4 = \frac{4}{3} m$ $=(12g)/(36g)*4=4/3m$

A balanced lever has two weights on it, the first with mass 12kg12 kg and the second with mass 36kg36 kg. If the first weight is 4m 4 m from the fulcrum, how far is the second weight from the fulcrum?