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A balanced lever has two weights on it, the first with mass $12 k g$ $12 kg$ and the second with mass $32 k g$ $32 kg$ . If the first weight is $1 m$ $1 m$ from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Feb 3, 2016

$12 \times 1 = 32 \times x$ $12xx1 = 32xxx$
Solve for x?
$x = \frac{3}{8}$ $x = 3/8$

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