A balanced lever has two weights on it, the first with mass $15 kg$ and the second with mass $5 kg$ . If the first weight is $2 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-03-05T08:26:37

The distance is $=6m$

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Here, we have

$M_1=15gN$

$M_2=5gN$

$a=2m$

Taking moments about the fulcrum

$M_1*a=M_2*b$

$b=M_1/M_2*a$

$=(15g)/(5)*2=6m$

A balanced lever has two weights on it, the first with mass 15 kg 15 kg and the second with mass 5 kg5 kg. If the first weight is 2 m 2 m from the fulcrum, how far is the second weight from the fulcrum?