A balanced lever has two weights on it, the first with mass $15 kg$ and the second with mass $9 kg$ . If the first weight is $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

Question

1350 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-09T14:49:34

The distance is $=6.67m$

The moments on both sides of the fulcrum must de equal on equilibrium.

$Moment =$ Force x distance

So,

Moment of first weight $=15g*4=60g Nm$

Moment of the second weight $=9g*d Nm$

Where $d=$ distance from the fulcum

On equilibrium

$60g=9g*d$

$d=60/9=20/3=6.67m$

A balanced lever has two weights on it, the first with mass 15 kg 15 kg and the second with mass 9 kg9 kg. If the first weight is 4 m 4 m from the fulcrum, how far is the second weight from the fulcrum?