A balanced lever has two weights on it, the first with mass 15 kg and the second with mass 9 kg. If the first weight is 4 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer
Dec 9, 2016

The distance is =6.67m

Explanation:

The moments on both sides of the fulcrum must de equal on equilibrium.

Moment =Force x distance

So,

Moment of first weight =15g*4=60g Nm

Moment of the second weight =9g*d Nm

Where d= distance from the fulcum

On equilibrium

60g=9g*d

d=60/9=20/3=6.67m