A balanced lever has two weights on it, the first with mass $15 k g$ $15 kg$ and the second with mass $27 k g$ $27 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass $15 k g$ $15 kg$ and the second with mass $27 k g$ $27 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-02-15T09:44:24

$x = \frac{40}{9} m$ $x=40/9 m$

Explanation:

$(the first mass) X (distance from fulcrum)=(the second mass) X (distance from fulcrum)$ $"(the first mass) X (distance from fulcrum)=(the second mass) X (distance from fulcrum)"$
$15 \cdot 8 = 27 \cdot x$ $15*8=27*x$
$x = \frac{120}{27}$ $x=120/27$
$x = \frac{40}{9} m$ $x=40/9 m$

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A balanced lever has two weights on it, the first with mass $15 k g$ $15 kg$ and the second with mass $27 k g$ $27 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass 15 kg 15kg15 kg and the second with mass 27 kg27kg27 kg. If the first weight is 8 m8m 8 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

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A balanced lever has two weights on it, the first with mass $15 k g$ $15 kg$ and the second with mass $27 k g$ $27 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?