A balanced lever has two weights on it, the first with mass $15 kg$ and the second with mass $18 kg$ . If the first weight is $6 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-04-11T06:40:27

The distance is $=5m$

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Here, we have

$M_2=15gN$

$b=6m$

$M_1=18gN$

Taking moments about the fulcrum

$15g*6=18g*a$

$a=(15*6)/18=5m$

A balanced lever has two weights on it, the first with mass 15 kg 15 kg and the second with mass 18 kg18 kg. If the first weight is 6 m 6 m from the fulcrum, how far is the second weight from the fulcrum?