A balanced lever has two weights on it, the first with mass $15 k g$ $15 kg$ and the second with mass $18 k g$ $18 kg$ . If the first weight is $9 m$ $9 m$ from the fulcrum, how far is the second weight from the fulcrum?

Question

1481 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-03T05:38:39

$7.5$ $7.5$ meters

For a balanced lever, we have:

$m_{1} d_{1} = m_{2} d_{2}$ $m_1d_1=m_2d_2$

$m_{1}, m_{2}$ $m_1,m_2$ are the masses of the two objects

$d_{1}, d_{2}$ $d_1,d_2$ are the distances of the two objects from the fulcrum

And so, we got:

$15 \ "kg"*9 \ "m"=18 \ "kg"*d_2$

$d_2=(135color(red)cancelcolor(black)"kg""m")/(18color(red)cancelcolor(black)"kg")$

$=7.5 \ "m"$

A balanced lever has two weights on it, the first with mass 15 kg 15kg15 kg and the second with mass 18 kg18kg18 kg. If the first weight is 9 m9m 9 m from the fulcrum, how far is the second weight from the fulcrum?