A balanced lever has two weights on it, the first with mass $15 k g$ $15 kg$ and the second with mass $14 k g$ $14 kg$ . If the first weight is $7 m$ $7 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass $15 k g$ $15 kg$ and the second with mass $14 k g$ $14 kg$ . If the first weight is $7 m$ $7 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-02-10T17:58:46

$b = 7, 5 m$ $b=7,5 m$

Explanation:

$F : the first weight$ $F:" the first weight"$
$S : the second weight$ $S:" the second weight"$
$a : distance between the first weight and fulcrum$ $a: " distance between the first weight and fulcrum"$
$b : distance between the second weight and fulcrum$ $b:" distance between the second weight and fulcrum"$
$F \cdot a = S \cdot b$ $F*a=S*b$
$15*cancel(7)=cancel(14)*b$
$15=2*b$
$b=7,5 m$

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A balanced lever has two weights on it, the first with mass $15 k g$ $15 kg$ and the second with mass $14 k g$ $14 kg$ . If the first weight is $7 m$ $7 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass 15 kg 15kg15 kg and the second with mass 14 kg14kg14 kg. If the first weight is 7 m7m 7 m from the fulcrum, how far is the second weight from the fulcrum?

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Explanation:

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A balanced lever has two weights on it, the first with mass $15 k g$ $15 kg$ and the second with mass $14 k g$ $14 kg$ . If the first weight is $7 m$ $7 m$ from the fulcrum, how far is the second weight from the fulcrum?