A balanced lever has two weights on it, the first with mass $15 kg$ and the second with mass $9 kg$ . If the first weight is $6 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-07-01T05:54:14

10m

The torques balance each other. therefore,
$r_1xxF_1=r_2xxF_2$
$F=m*g$
$m_1*g*r_1=m_2*g*r_2$
$15xxgxx6=9xxgxxr_2$

Solving this equation we get $r_2=10m$

A balanced lever has two weights on it, the first with mass 15 kg 15 kg and the second with mass 9 kg9 kg. If the first weight is 6 m 6 m from the fulcrum, how far is the second weight from the fulcrum?