A balanced lever has two weights on it, the first with mass $2 k g$ $2 kg$ and the second with mass $1 k g$ $1 kg$ . If the first weight is $7 m$ $7 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-03-16T17:29:27

$x = 14 m$ $x=14 m$

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$G_{1} \cdot A C = G_{2} \cdot B C$ $G_1*AC=G_2*BC$
$2*cancel(9,81)*7=1*cancel(9,81)*x$
$x=14 m$

A balanced lever has two weights on it, the first with mass 2 kg 2kg2 kg and the second with mass 1 kg1kg1 kg. If the first weight is 7 m7m 7 m from the fulcrum, how far is the second weight from the fulcrum?