A balanced lever has two weights on it, the first with mass $2 k g$ $2 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

Question

1389 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-02T15:11:07

The distance is $= 0.89 m$ $=0.89m$

www.thoughtco.com

The mass $M_{1} = 2 k g$ $M_1=2kg$

The mass $M_{2} = 9 k g$ $M_2=9kg$

The distance $a = 4 m$ $a=4m$

Taking moments about the fulcrum

$M_{1} \times a = M_{2} \times b$ $M_1xxa=M_2xxb$

$b = \frac{M_{1} \times a}{M_{2}} = \frac{4 \times 2}{9} = 0.89 m$ $b=(M_1xxa)/(M_2)=(4xx2)/(9)=0.89m$

A balanced lever has two weights on it, the first with mass 2kg2 kg and the second with mass 9kg9 kg. If the first weight is 4m 4 m from the fulcrum, how far is the second weight from the fulcrum?