A balanced lever has two weights on it, the first with mass $2 k g$ $2 kg$ and the second with mass $38 k g$ $38 kg$ . If the first weight is $18 m$ $18 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass $2 k g$ $2 kg$ and the second with mass $38 k g$ $38 kg$ . If the first weight is $18 m$ $18 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2015-12-11T10:41:18

This problem can be easily solved by "Law of moments" which is just equating net torque on the system to zero.

Explanation:

Moment due to the $m_{1}$ $m_1$ =2kg mass at $l_{1}$ $l_1$ =18m= $m_{1} l_{1}$ $m_1l_1$ = $2 \times 18$ $2\times18$ = $36$ $36$
let it be at a distance $x$ $x$ from the fulcrum.
Moment due to the $m_{2}$ $m_2$ =38kg mass at $l_{2}$ $l_2$ = $x$ $x$ distance= $38 x$ $38x$
Law of moments says-
$m_{1} l_{1} = m_{2} l_{2}$ $m_1 l_1=m_2 l_2$
$38 x = 36$ $38x=36$
$x = \frac{36}{38} m = \frac{18}{19} m = 0.94 m$ $x=\frac{36}{38}m=\frac{18}{19}m=0.94m$

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A balanced lever has two weights on it, the first with mass $2 k g$ $2 kg$ and the second with mass $38 k g$ $38 kg$ . If the first weight is $18 m$ $18 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Explanation:

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A balanced lever has two weights on it, the first with mass 2 kg 2kg2 kg and the second with mass 38 kg38kg38 kg. If the first weight is 18 m18m 18 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

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A balanced lever has two weights on it, the first with mass $2 k g$ $2 kg$ and the second with mass $38 k g$ $38 kg$ . If the first weight is $18 m$ $18 m$ from the fulcrum, how far is the second weight from the fulcrum?