A balanced lever has two weights on it, the first with mass $22 k g$ $22 kg$ and the second with mass $21 k g$ $21 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-04-15T01:59:34

$4.2 \ "m"$

For a balanced lever, we have the following relationship:

$m_1d_1=m_2d_2$

$m_1,m_2$ are the masses of the two objects

$d_1,d_2$ are the distances of the two objects from the fulcrum

And so,

$22 \ "kg"*4 \ "m"=21 \ "kg"*d_2$

$d_2=(22color(red)cancelcolor(black)"kg"*4 \ "m")/(21color(red)cancelcolor(black)"kg")$

$~~4.2 \ "m"$

A balanced lever has two weights on it, the first with mass 22 kg 22kg22 kg and the second with mass 21 kg21kg21 kg. If the first weight is 4 m4m 4 m from the fulcrum, how far is the second weight from the fulcrum?