A balanced lever has two weights on it, the first with mass $24 k g$ $24 kg$ and the second with mass $48 k g$ $48 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-03-29T07:01:23

The distance is $= 2 m$ $=2m$

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$M_{2} = 24 g N$ $M_2=24g N$

$b = 4 m$ $b=4m$

$M_{1} = 48 g N$ $M_1=48gN$

Taking moments about the fulcrum

$M_{1} \cdot a = M_{2} \cdot b$ $M_1*a=M_2*b$

$48 g \cdot a = 24 g \cdot 4$ $48g*a=24g*4$

$b = \frac{24 g \cdot 4}{48 g}$ $b=(24g*4)/(48g)$

$= 2 m$ $=2m$

A balanced lever has two weights on it, the first with mass 24kg24 kg and the second with mass 48kg48 kg. If the first weight is 4m 4 m from the fulcrum, how far is the second weight from the fulcrum?