A balanced lever has two weights on it, the first with mass 3 kg 3kg and the second with mass 4 kg4kg. If the first weight is 5 m5m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer
Alan P.
Mar 25, 2016

3 3/4334 meters

Explanation:

Let xx be the distance the second weight is from the fulcrum.

Since the lever is balanced
color(white)("XXX")3kg xx 5 m = 4 kg xx xXXX3kg×5m=4kg×x

rarrcolor(white)("XXX")x=(3 cancel(kg)xx5m)/(4cancel(kg))=3 3/4 m

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