A balanced lever has two weights on it, the first with mass $3 k g$ $3 kg$ and the second with mass $25 k g$ $25 kg$ . If the first weight is $6 m$ $6 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-04-20T05:57:08

The distance is $= 1.44 m$ $=1.44m$

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Mass, $M_{2} = 6 k g$ $M_2=6kg$

Mass, $M_{1} = 25 k g$ $M_1=25kg$

Distance, $b = 6 m$ $b=6m$

Taking moments about the fulcrum

$M_{1} \cdot a = M_{2} \cdot b$ $M_1*a=M_2*b$

$a = \frac{M_{2}}{M_{1}} \cdot b$ $a=M_2/M_1*b$

$= \frac{6 g}{25 g} \cdot 6 = 1.44 m$ $=(6g)/(25g)*6=1.44m$

A balanced lever has two weights on it, the first with mass 3kg3 kg and the second with mass 25kg25 kg. If the first weight is 6m 6 m from the fulcrum, how far is the second weight from the fulcrum?