A balanced lever has two weights on it, the first with mass $3 kg$ and the second with mass $25 kg$ . If the first weight is $6 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-04-20T05:57:08

The distance is $=1.44m$

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Mass, $M_2=6kg$

Mass, $M_1=25kg$

Distance, $b=6m$

Taking moments about the fulcrum

$M_1*a=M_2*b$

$a=M_2/M_1*b$

$=(6g)/(25g)*6=1.44m$

A balanced lever has two weights on it, the first with mass 3 kg 3 kg and the second with mass 25 kg25 kg. If the first weight is 6 m 6 m from the fulcrum, how far is the second weight from the fulcrum?