A balanced lever has two weights on it, the first with mass $3 k g$ $3 kg$ and the second with mass $7 k g$ $7 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-04-19T06:32:02

The distance is $= 3.43 m$ $=3.43m$

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Mass, $M_{2} = 3 k g$ $M_2=3kg$

Mass, $M_{1} = 7 k g$ $M_1=7kg$

Distance, $b = 8 m$ $b=8m$

Taking moments about the fulcrum

$M_{1} \cdot a = M_{2} \cdot b$ $M_1*a=M_2*b$

$a = \frac{M_{2}}{M_{1}} \cdot b$ $a=M_2/M_1*b$

$= \frac{3 g}{7 g} \cdot 8 = \frac{24}{7} m$ $=(3g)/(7g)*8=24/7m$

A balanced lever has two weights on it, the first with mass 3 kg 3kg3 kg and the second with mass 7 kg7kg7 kg. If the first weight is 8 m8m 8 m from the fulcrum, how far is the second weight from the fulcrum?