A balanced lever has two weights on it, the first with mass $34 k g$ $34 kg$ and the second with mass $68 k g$ $68 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass $34 k g$ $34 kg$ and the second with mass $68 k g$ $68 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-05-16T04:42:38

The second weight $68 k g$ $68kg$ is $1.5 m$ $1.5m$ from the fulcrum.

Explanation:

The balanced lever is a simple scale in this configuration.
If the two weights balance each other then the distance from the fulcrum to each must be in proportion to the two weights.

That is: $w_{1} \cdot d_{1} = w_{2} . d_{2}$ $w_1*d_1=w_2.d_2$

We were told that:

$w_{1} = 34 k g; w_{2} = 68 k g; d_{1} = 3 m$ $w_1=34kg; w_2=68kg; d_1=3m$

So: $34 k g \cdot 3 m = 68 k g \cdot d_{2}$ $34kg*3m=68kg*d_2$

$cancel(34kg)*3m=cancel(68kg)*d_2$

$2d_2=3m$

$d_2=1.5m$

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A balanced lever has two weights on it, the first with mass $34 k g$ $34 kg$ and the second with mass $68 k g$ $68 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

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Humanities

... and beyond

A balanced lever has two weights on it, the first with mass 34 kg 34kg34 kg and the second with mass 68 kg68kg68 kg. If the first weight is 3 m3m 3 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

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A balanced lever has two weights on it, the first with mass $34 k g$ $34 kg$ and the second with mass $68 k g$ $68 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?