A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $6 k g$ $6 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

Question

A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $6 k g$ $6 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Impact of this question

1549 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-29T18:17:25

$2.667 m$ $2.667m$

Explanation:

The second condition for static equilibrium states that the result torque (moments of the forces) must be zero.
That is, $\sum \to τ = 0$ $sumvectau=0$ , where $\to τ = \to r \times \to F$ $vectau = vecr xx vecF$ is the algebraic vector cross product of the position vector from the axis of rotation (fulcrum) to the applied force, and the applied force itself.

Application thereof in this particular case gives

$r_{1} F_{1} - r_{2} F_{2} = 0$ $r_1F_1-r_2F_2=0$

$therefore(4xx4g)-(r_2xx6g)=0$

$therefore r_2=(4xx4xx9.8)/(6xx9,8)=2.667m$ .

Science

Math

Humanities

... and beyond

A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $6 k g$ $6 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

A balanced lever has two weights on it, the first with mass 4 kg 4kg4 kg and the second with mass 6 kg6kg6 kg. If the first weight is 4 m4m 4 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

Related questions

Impact of this question

A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $6 k g$ $6 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?