A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $6 k g$ $6 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $6 k g$ $6 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-04-03T18:08:28

The equation is $F_{L} \times d_{L} = F_{R} \times d_{R}$ $F_Lxxd_L=F_Rxxd_R$
Where $F =$ $F=$ force, $d =$ $d=$ distance, $L =$ $L=$ left, $R = r i g h t$ $R=right$

Explanation:

When we translate the masses into forces, we have the constant $g$ $g$ on both sides, so they cancel. The equation then turns into:
$m_Lxxcancelgxxd_L=m_Rxxcancelgxxd_R$

$4kgxx8m=6kgxxd_R$

$d_R=(4cancel(kg)xx8m)/(6cancel(kg))=32/6m=5 1/3m$

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A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $6 k g$ $6 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Explanation:

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A balanced lever has two weights on it, the first with mass 4 kg 4kg4 kg and the second with mass 6 kg6kg6 kg. If the first weight is 8 m8m 8 m from the fulcrum, how far is the second weight from the fulcrum?

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Explanation:

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A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $6 k g$ $6 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?