A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $2 k g$ $2 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-11-10T07:08:06

The distance is $= 6 m$ $=6m$

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The mass $M_{1} = 4 k g$ $M_1=4kg$

The mass $M_{2} = 2 k g$ $M_2=2kg$

The distance $a = 3 m$ $a=3m$

Taking moments about the fulcrum

$M_{1} \times a = M_{2} \times b$ $M_1xxa=M_2xxb$

$b = \frac{M_{1} \times a}{M_{2}} = \frac{4 \cdot 3}{2} = 6 m$ $b=(M_1xxa)/(M_2)=(4*3)/(2)=6m$

The distance $b = 6 m$ $b=6m$

A balanced lever has two weights on it, the first with mass 4kg4 kg and the second with mass 2kg2 kg. If the first weight is 3m 3 m from the fulcrum, how far is the second weight from the fulcrum?