A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-03-07T18:15:48

$1.78 m$ $1.78m$

Explanation:

apply the formula $F_{1} \cdot d_{1} = F_{2} \cdot d_{2}$ $F_1 * d_1 = F_2 *d_2$
$4 \cdot 4 = 9 \cdot d_{2}$ $4*4=9 * d_2$
$d_{2} = 1.78 m$ $d_2=1.78m$

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A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass 4kg4 kg and the second with mass 9kg9 kg. If the first weight is 4m 4 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

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A balanced lever has two weights on it, the first with mass $4 k g$ $4 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?