A balanced lever has two weights on it, the first with mass $5 k g$ $5 kg$ and the second with mass $60 k g$ $60 kg$ . If the first weight is $6 m$ $6 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass $5 k g$ $5 kg$ and the second with mass $60 k g$ $60 kg$ . If the first weight is $6 m$ $6 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-02-12T15:05:08

$b = \frac{1}{2} = 0, 5 m$ $b=1/2=0,5 m$

Explanation:

$F_{1} : First weight$ $F_1:" First weight"$
$F_{2} : second weight$ $F_2:" Second weight"$
$a : distance between F_1 and fulcrum$ $a:" distance between F_1 and fulcrum"$
$b : distance between F_2 and fulcrum$ $b:" distance between F_2 and fulcrum"$
$you can write balance equation by:$ $"you can write balance equation by:"$
$F_{1} \cdot a = F_{2} \cdot b$ $F_1*a=F_2*b$
$5 \cdot 6 = 60 \cdot b$ $5*6=60*b$
$cancel(30)=cancel(60)*b$
$b=1/2=0,5 m$

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A balanced lever has two weights on it, the first with mass $5 k g$ $5 kg$ and the second with mass $60 k g$ $60 kg$ . If the first weight is $6 m$ $6 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Explanation:

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A balanced lever has two weights on it, the first with mass 5 kg 5kg5 kg and the second with mass 60 kg60kg60 kg. If the first weight is 6 m6m 6 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

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A balanced lever has two weights on it, the first with mass $5 k g$ $5 kg$ and the second with mass $60 k g$ $60 kg$ . If the first weight is $6 m$ $6 m$ from the fulcrum, how far is the second weight from the fulcrum?