A balanced lever has two weights on it, the first with mass $5 k g$ $5 kg$ and the second with mass $7 k g$ $7 kg$ . If the first weight is $6 m$ $6 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-06-10T06:41:46

The distance is $= 4.29 m$ $=4.29m$

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The mass $M_{1} = 5 k g$ $M_1=5kg$

The mass $M_{2} = 7 k g$ $M_2=7kg$

The distance $a = 6 m$ $a=6m$

Taking moments about the fulcrum

$M_{1} \times a = M_{2} \times b$ $M_1xxa=M_2xxb$

$b = \frac{M_{1} \times a}{M_{2}} = \frac{5 \times 6}{7} = 4.29 m$ $b=(M_1xxa)/(M_2)=(5xx6)/(7)=4.29m$

A balanced lever has two weights on it, the first with mass 5kg5 kg and the second with mass 7kg7 kg. If the first weight is 6m 6 m from the fulcrum, how far is the second weight from the fulcrum?