A balanced lever has two weights on it, the first with mass $5 k g$ $5 kg$ and the second with mass $4 k g$ $4 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-02-09T09:40:48

$x = 3, 75 m$ $x=3,75 " m"$

$5 \cdot 3 = 4 \cdot x$ $5*3=4*x$
$15 = 4 \cdot x$ $15=4*x$
$x = \frac{15}{4}$ $x=15/4$
$x = 3, 75 m$ $x=3,75 " m"$

A balanced lever has two weights on it, the first with mass 5kg5 kg and the second with mass 4kg4 kg. If the first weight is 3m 3 m from the fulcrum, how far is the second weight from the fulcrum?