A balanced lever has two weights on it, the first with mass $5 k g$ $5 kg$ and the second with mass $8 k g$ $8 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass $5 k g$ $5 kg$ and the second with mass $8 k g$ $8 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-05-01T12:38:45

$x = 2.5 m$ $x=2.5m$

Explanation:

First of all remember that the principle of moments must apply which is the anticlockwise moment=clockwise moment.
Now use the formula $F \cdot d = F \cdot d$ $F*d=F*d$
but before that convert the masses into weight by multiplying by 10
which is the gravitational force so
$5 \cdot 10 = 50 N$ $5*10=50N$
$8 \cdot 10 = 80 N$ $8*10=80N$
no using the formula
$50 \cdot 4 = 80 \cdot x$ $50*4=80*x$
$x = 2.5 m$ $x=2.5m$

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A balanced lever has two weights on it, the first with mass $5 k g$ $5 kg$ and the second with mass $8 k g$ $8 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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A balanced lever has two weights on it, the first with mass 5kg5 kg and the second with mass 8kg8 kg. If the first weight is 4m 4 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

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A balanced lever has two weights on it, the first with mass $5 k g$ $5 kg$ and the second with mass $8 k g$ $8 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?