A balanced lever has two weights on it, the first with mass $5 kg$ and the second with mass $8 kg$ . If the first weight is $7 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-03-29T06:57:44

The distance is $=4.375m$

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$M_2=5g N$

$b=7m$

$M_1=8gN$

Taking moments about the fulcrum

$M_1*a=M_2*b$

$8g*a=5g*7$

$b=(5g*7)/(8g)$

$=4.375m$

A balanced lever has two weights on it, the first with mass 5 kg 5 kg and the second with mass 8 kg8 kg. If the first weight is 7 m 7 m from the fulcrum, how far is the second weight from the fulcrum?