A balanced lever has two weights on it, the first with mass $5 kg$ and the second with mass $35 kg$ . If the first weight is $9 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-12-12T21:22:22

$= 1.29m (3s.f.)$

use turning moments:

$M_1 * D_1 = M_2 * D_2$

( $M$ being mass of weight on lever, $D$ being distance from fulcrum)

$M_1 = 5kg$
$M_2 = 35kg$

$D_1 = 9m$

find $D_2$ :

$M_1 * D_1 = 5 * 9 = 45$
$M_2 * D_2 = 35 * D_2 = 45$

$D_2 = (45/35) m$

$= (9/7)m$

$= 1.29m (3s.f.)$

A balanced lever has two weights on it, the first with mass 5 kg 5 kg and the second with mass 35 kg35 kg. If the first weight is 9 m 9 m from the fulcrum, how far is the second weight from the fulcrum?