A balanced lever has two weights on it, the first with mass $6 kg$ and the second with mass $7 kg$ . If the first weight is $5 m$ from the fulcrum, how far is the second weight from the fulcrum?

Question

2115 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-25T15:51:04

The distance is $=4.28m$

enter image source here

The load $L=6gN$

The distance of the load from the fulcrum is $=5m$

The effort is $E=7gN$

The distance of the effort to the fulcrum is $xm$

In a situation of equilibrium, the moments are equal

So,

$6*5=7*x$

$x=30/7=4.28m$

A balanced lever has two weights on it, the first with mass 6 kg 6 kg and the second with mass 7 kg7 kg. If the first weight is 5 m 5 m from the fulcrum, how far is the second weight from the fulcrum?