A balanced lever has two weights on it, the first with mass 6 kg and the second with mass 4 kg. If the first weight is 5 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer
Feb 25, 2016

Second weight is 7.5 m far from fulcrum.

Explanation:

Let the the second weight be x m far from the fulcrum.

As the lever is balanced, moment (M=F*d, where F is force applied and d is its distance from fulcrum) of the two weights should be equal.

Moment of first weight is 6*5=30 and as it balances second weight of 4 kg, the latter's distance should be

30/4=7.5 m.