A balanced lever has two weights on it, the first with mass $6 kg$ and the second with mass $4 kg$ . If the first weight is $5 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-02-25T16:13:55

Second weight is $7.5$ $m$ far from fulcrum.

Let the the second weight be $x$ $m$ far from the fulcrum.

As the lever is balanced, moment ( $M=F*d$ , where $F$ is force applied and $d$ is its distance from fulcrum) of the two weights should be equal.

Moment of first weight is $6*5=30$ and as it balances second weight of $4$ kg, the latter's distance should be

$30/4=7.5$ $m$ .

A balanced lever has two weights on it, the first with mass 6 kg 6 kg and the second with mass 4 kg4 kg. If the first weight is 5 m 5 m from the fulcrum, how far is the second weight from the fulcrum?