A balanced lever has two weights on it, the first with mass $6 kg$ and the second with mass $7 kg$ . If the first weight is $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-05-07T05:51:08

The distance is $=3.43m$

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The mass $M_1=6kg$

The mass $M_2=7kg$

The distance $a=4m$

Taking moments about the fulcrum

$M_1xxa=M_2xxb$

$b=(M_1xxa)/(M_2)=(6xx4)/(7)=3.43m$

A balanced lever has two weights on it, the first with mass 6 kg 6 kg and the second with mass 7 kg7 kg. If the first weight is 4 m 4 m from the fulcrum, how far is the second weight from the fulcrum?