A balanced lever has two weights on it, the first with mass $6 kg$ and the second with mass $8 kg$ . If the first weight is $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-06-23T18:32:21

The distance is $=3m$

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The acceleration due to gravity is $g=9.8ms^-2$

The mass $M_1=6kg$

The mass $M_2=8kg$

The distance $a=4m$

Taking moments about the fulcrum

$M_1gxxa=M_2gxxb$

So,

$6gxx4=8gxxb$

$b=(24g)/(8g)=3m$

A balanced lever has two weights on it, the first with mass 6 kg 6 kg and the second with mass 8 kg8 kg. If the first weight is 4 m 4 m from the fulcrum, how far is the second weight from the fulcrum?