A balanced lever has two weights on it, the first with mass $6 k g$ $6 kg$ and the second with mass $27 k g$ $27 kg$ . If the first weight is $8 m$ $8 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-02-05T20:46:14

$\frac{16}{9} = 1 \frac{7}{9}$ $16/9 = 1 7/9$ m.

$6 kgm \times 8 m = 27 kgm \times ?$ $6 " kgm" xx 8 " m" = 27 " kgm" xx ?$

$?= (6 cancel(" kgm")xx8 " m")/(27 cancel(" kgm")) = (2xx8 " m")/9 = 16/9 " m"$

A balanced lever has two weights on it, the first with mass 6 kg 6kg6 kg and the second with mass 27 kg27kg27 kg. If the first weight is 8 m8m 8 m from the fulcrum, how far is the second weight from the fulcrum?