A balanced lever has two weights on it, the first with mass $66 k g$ $66 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $1 m$ $1 m$ from the fulcrum, how far is the second weight from the fulcrum?

Question

A balanced lever has two weights on it, the first with mass $66 k g$ $66 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $1 m$ $1 m$ from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Impact of this question

1421 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-21T18:13:02

The $9 k g$ $9 kg$ mass should be $7.33 m$ $7.33 m$ from the fulcrum.

Explanation:

For this solution we will use the formula $F_{1} d_{1} = F_{2} d_{2}$ $F_1d_1 = F_2d_2$

Where Force times the distance of one side of the lever must equal the combination of the Force and distance applied on the opposite side of the lever.

Force equals mass time gravity

$F = m \cdot g$ $F = m*g$

$F_{1} = 66 k g \cdot 9.81 \frac{m}{s^{2}} = 647.46 N$ $F_1 = 66kg*9.81m/s^2 = 647.46 N$

$F_{2} = 9 k g \cdot 9.81 \frac{m}{s^{2}} = 88.29 N$ $F_2 = 9kg*9.81m/s^2 = 88.29 N$

$d_{1} = 1 m$ $d_1 = 1m$

$d_{2} = ?$ $d_2 = ?$

$F_{1} d_{1} = F_{2} d_{2}$ $F_1d_1 = F_2d_2$

$(647.46 N) (1 m) = (88.29 N) (d_{2})$ $(647.46N)(1 m) = (88.29N)(d_2)$

$(647.46cancelN*m)/(88.29 cancelN) = ((cancel(88.29N))(d_2))/(cancel(88.29N)$

$d_2 = 7.33 m$

Science

Math

Humanities

... and beyond

A balanced lever has two weights on it, the first with mass $66 k g$ $66 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $1 m$ $1 m$ from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

A balanced lever has two weights on it, the first with mass 66 kg 66kg66 kg and the second with mass 9 kg9kg9 kg. If the first weight is 1 m1m 1 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer

Explanation:

Related questions

Impact of this question

A balanced lever has two weights on it, the first with mass $66 k g$ $66 kg$ and the second with mass $9 k g$ $9 kg$ . If the first weight is $1 m$ $1 m$ from the fulcrum, how far is the second weight from the fulcrum?