A balanced lever has two weights on it, the first with mass 7 kg and the second with mass 3 kg. If the first weight is 2 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer
Feb 13, 2016

4.667 meters

Explanation:

In a balanced lever, product of mass of one weight and its distance from fulcrum is equal to the mass of other weight and its distance from the fulcrum. As the product is 14 in first weight, the distance of second weight from fulcrum would be 14/3 i.e. 4.667 meters.