A balanced lever has two weights on it, the first with mass $7 kg$ and the second with mass $30 kg$ . If the first weight is $7 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-03-16T09:25:10

The distance is $=1.63m$

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The first mass is $M_1=7kg$

The distance $a=7m$

The second mass is $M_2=30kg$

Taking moments about the fulcrum

$M_2xxb=M_1xxa$

The distance

$b=(M_1xxa)/(M_2)=(7*7)/30=1.63m$

A balanced lever has two weights on it, the first with mass 7 kg 7 kg and the second with mass 30 kg30 kg. If the first weight is 7 m 7 m from the fulcrum, how far is the second weight from the fulcrum?