A balanced lever has two weights on it, the first with mass $8 kg$ and the second with mass $64 kg$ . If the first weight is $12 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-04-13T07:14:46

The distance is $=1.5m$

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The first weight is $M_2=(8g)N$

The second weight is $M_1=(64g)N$

The first distance is $b=12m$

Taking moments about the fulcrum

$M_1*a=M_2*b$

$a=(M_2*b)/M_1=(8g*12)/(64g)=1.5m$

A balanced lever has two weights on it, the first with mass 8 kg 8 kg and the second with mass 64 kg64 kg. If the first weight is 12 m 12 m from the fulcrum, how far is the second weight from the fulcrum?