A balanced lever has two weights on it, the first with mass $9 k g$ $9 kg$ and the second with mass $4 k g$ $4 kg$ . If the first weight is $3 m$ $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-04-29T14:17:19

$x = 6.75$ $x= 6.75" "$ meters

Let $x$ $x" "$ be the unknown distance

Summation of Moments about the fulcrum equals to zero.

Taking clockwise positive

$- 9 \cdot 3 + 4 \cdot x = 0$ $-9*3+4*x=0$

$x = \frac{27}{4}$ $x=27/4$

$x = 6.75$ $x=6.75" "$ meters

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A balanced lever has two weights on it, the first with mass 9 kg 9kg9 kg and the second with mass 4 kg4kg4 kg. If the first weight is 3 m3m 3 m from the fulcrum, how far is the second weight from the fulcrum?