A balanced lever has two weights on it, the first with mass $9 k g$ $9 kg$ and the second with mass $4 k g$ $4 kg$ . If the first weight is $12 m$ $12 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2018-07-01T06:11:14

The distance is $= 27 m$ $=27m$

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The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

The mass $M_{1} = 9 k g$ $M_1=9kg$

The mass $M_{2} = 4 k g$ $M_2=4kg$

The distance $a = 12 m$ $a=12m$

Taking moments about the fulcrum

$M_{1} g \times a = M_{2} g \times b$ $M_1gxxa=M_2gxxb$

So,

$9 g \times 12 = 4 g \times b$ $9gxx12=4gxxb$

$b = \frac{108 g}{4 g} = 27 m$ $b=(108g)/(4g)=27m$

A balanced lever has two weights on it, the first with mass 9 kg 9kg9 kg and the second with mass 4 kg4kg4 kg. If the first weight is 12 m12m 12 m from the fulcrum, how far is the second weight from the fulcrum?