A balanced lever has two weights on it, the first with mass $9 k g$ $9 kg$ and the second with mass $32 k g$ $32 kg$ . If the first weight is $4 m$ $4 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-08-25T05:17:00

The distance is $= 1.125 m$ $=1.125m$

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The mass $M_{2} = 9 k g$ $M_2=9kg$

The mass $M_{1} = 32 k g$ $M_1=32kg$

The distance $b = 4 m$ $b=4m$

Taking the moments about the fulcrum

$M_{1} \cdot g \cdot a = M_{2} \cdot g \cdot b$ $M_1*g*a=M_2*g*b$

$32 \cdot g \cdot a = 9 \cdot g \cdot 4$ $32*g*a=9*g*4$

$a = \frac{36}{32} = 1.125 m$ $a=36/32=1.125m$

A balanced lever has two weights on it, the first with mass 9kg9 kg and the second with mass 32kg32 kg. If the first weight is 4m 4 m from the fulcrum, how far is the second weight from the fulcrum?