A ball is projected vertically upward with a velocity of 30m/s. 2s later another ball is released from the top of a story building 80m tall. Determine after what time the balls bi pass each other and at what height do they bi pass?
1 Answer
Mar 21, 2018
4 s after the second ball is dropped, at the ground (I have assumed
Explanation:
In 2s, the first ball will rise a distance of
At this instant, its speed is
At this instant, the second ball is dropped. Now
- the relative separation of the two balls
- their relative velocity
- their relative acceleration
Thus the time it takes for the two to meet is
In this time, the second ball will drop a distance of
Thus the two balls will meet at the ground!