Question

A ball is thrown into the air from the roof of the building. Its height (in feet) t seconds later is given by h(t)=80+80t-16t^2. What is the initial height of the ball?

Answer 1

`80` ft.

Explanation:

At time `t=0` (the initial time)
`color(white)("XXX")h(0) = 80+80(0)-16(0)^2 = 80` feet