A ball with a mass of $120 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $96 (kg)/s^2$ and was compressed by $4/3 m$ when the ball was released. How high will the ball go?

Question

1379 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-09T09:55:21

The height is $=72.56m$

enter image source here

The spring constant is $k=96kgs^-2$

The compression is $x=4/3m$

The potential energy in the spring is

$PE=1/2*96*(4/3)^2=85.3J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

$PE_(ball)=85.3=0.12*9.8*h$

$h=85.3*1/(0.12*9.8)$

$=72.56m$

A ball with a mass of 120 g120 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 96 (kg)/s^296 (kg)/s^2 and was compressed by 4/3 m4/3 m when the ball was released. How high will the ball go?