A ball with a mass of $125 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $16 (kg)/s^2$ and was compressed by $2/5 m$ when the ball was released. How high will the ball go?

Question

1681 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-28T14:20:01

The height is $=0.52m$

enter image source here

The spring constant is $k=16kgs^-2$

The compression is $x=2/5m$

The potential energy is

$PE=1/2*16*(2/5)^2=1.28J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

The acceleration due to gravity is $g=9.8ms^-2$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

Mass of the ball is $m=0.125kg$

$PE_(ball)=1.28=0.25*9.8*h$

$h=1.28*1/(0.25*9.8)$

$=0.52m$

The height is $=0.52m$

A ball with a mass of 125 g125 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 16 (kg)/s^216 (kg)/s^2 and was compressed by 2/5 m2/5 m when the ball was released. How high will the ball go?