A ball with a mass of $140$ $g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $42$ $kgs^-2$ and was compressed by $5/3$ $m$ when the ball was released. How high will the ball go?

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A ball with a mass of $140$ $g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $42$ $kgs^-2$ and was compressed by $5/3$ $m$ when the ball was released. How high will the ball go?

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Answer 1 · 2016-07-19T20:25:59

The spring potential energy is $E_p=1/2kx^2=1/2xx42xx(5/3)^2=58.3$ $J$
This energy will be converted to gravitational potential energy, $E_p=mgh$ . Rearranging: $h=E_p/(mg)=58.3/(0.14xx9.8)=42.5$ $m$ (remembering to convert the mass to kg, the SI unit)

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A ball with a mass of $140$ $g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $42$ $kgs^-2$ and was compressed by $5/3$ $m$ when the ball was released. How high will the ball go?

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A ball with a mass of $140$ $g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $42$ $kgs^-2$ and was compressed by $5/3$ $m$ when the ball was released. How high will the ball go?