A ball with a mass of $140 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $42 (kg)/s^2$ and was compressed by $5/6 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2017-06-07T06:55:59

The height is $=10.63m$

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The spring constant is $k=42kgs^-2$

The compression is $x=5/6m$

The potential energy in the spring is

$PE=1/2*42*(5/6)^2=14.58J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

$PE_(ball)=14.58=0.14*9.8*h$

$h=14.58*1/(0.14*9.8)$

$=10.63m$

A ball with a mass of 140 g140 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 42 (kg)/s^242 (kg)/s^2 and was compressed by 5/6 m5/6 m when the ball was released. How high will the ball go?