A ball with a mass of $150 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $15 (kg)/s^2$ and was compressed by $7/5 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2017-08-26T05:35:09

The height of the ball is $=10m$

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The spring constant is $k=15kgs^-2$

The compression is $x=7/5m$

The potential energy in the spring is

$PE=1/2*15*(7/5)^2=14.7J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

The mass of the ball is $=0.150kg$

$PE_(ball)=14.7=0.650*9.8*h$

$h=14.7*1/(0.150*9.8)$

$=10m$

A ball with a mass of 150 g150 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 15 (kg)/s^215 (kg)/s^2 and was compressed by 7/5 m7/5 m when the ball was released. How high will the ball go?