A ball with a mass of $250 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $8 (kg)/s^2$ and was compressed by $3/2 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2018-05-31T06:32:34

The height reached by the ball is $=3.67m$

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The spring constant is $k=8kgs^-2$

The compression of the spring is $x=3/2m$

The potential energy stored in the spring is

$PE=1/2kx^2=1/2*8*(3/2)^2=9J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

The acceleration due to gravity is $g=9.8ms^-2$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

Mass of the ball is $m=0.250kg$

$PE_(ball)=9=0.250*9.8*h$

$h=9*1/(0.250*9.8)$

$=3.67m$

The height reached by the ball is $=3.67m$

A ball with a mass of 250 g250 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 8 (kg)/s^28 (kg)/s^2 and was compressed by 3/2 m3/2 m when the ball was released. How high will the ball go?