A ball with a mass of $256 g$ $256 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $24 \frac{k g}{s^{2}}$ $24 (kg)/s^2$ and was compressed by $\frac{4}{3} m$ $4/3 m$ when the ball was released. How high will the ball go?

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A ball with a mass of $256 g$ $256 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $24 \frac{k g}{s^{2}}$ $24 (kg)/s^2$ and was compressed by $\frac{4}{3} m$ $4/3 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2016-10-08T03:48:21

8,5 m

Explanation:

the final potential energy of the ball is the same of the elastic initial energy of the spring. Espring = 1/2 K X^2 = 1/2 x 24 x 16/9 = 21,3 J = E potential = mgh
h=E/mg = 21,3/(0,256 x9,8) = 8,5 m

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A ball with a mass of $256 g$ $256 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $24 \frac{k g}{s^{2}}$ $24 (kg)/s^2$ and was compressed by $\frac{4}{3} m$ $4/3 m$ when the ball was released. How high will the ball go?

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Explanation:

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A ball with a mass of 256 g256g256 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 24 (kg)/s^224kgs224 (kg)/s^2 and was compressed by 4/3 m43m4/3 m when the ball was released. How high will the ball go?

1 Answer

Explanation:

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A ball with a mass of $256 g$ $256 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $24 \frac{k g}{s^{2}}$ $24 (kg)/s^2$ and was compressed by $\frac{4}{3} m$ $4/3 m$ when the ball was released. How high will the ball go?