A ball with a mass of $300 g$ $300 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $54 \frac{k g}{s^{2}}$ $54 (kg)/s^2$ and was compressed by $\frac{7}{6} m$ $7/6 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2016-04-12T18:57:08

$h = 12, 49 meters$ $h=12,49 " meters"$

$E_p=1/2*K*Delta x^2$
$E_p=1/2*54*(7/6)^2$

$E_p=27*49/36$

$E_p=36,75J" stored energy for spring"$

$m*g*h=36,75$
$m=300" gr"=0,3" kg"$
$g=9,81 N/(kg)$

$h=(36,75)/(0,3*9,81)$

$h=(36,75)/(2,943)$

$h=12,49 " meters"$

A ball with a mass of 300 g300g300 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 54 (kg)/s^254kgs254 (kg)/s^2 and was compressed by 7/6 m76m7/6 m when the ball was released. How high will the ball go?